0.5551936219055919706209+b^2=10

Solution for 0.5551936219055919706209+b^2=10 equation:

0.5551936219055919706209+b^2=10

We move all terms to the left:

0.5551936219055919706209+b^2-(10)=0

We add all the numbers together, and all the variables

b^2-9.4448063780944=0

a = 1; b = 0; c = -9.4448063780944;
Δ = b2-4ac
Δ = 02-4·1·(-9.4448063780944)
Δ = 37.779225512378
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{37.779225512378}}{2*1}=\frac{0-\sqrt{37.779225512378}}{2}
=-\frac{\sqrt{}}{2}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{37.779225512378}}{2*1}=\frac{0+\sqrt{37.779225512378}}{2}
=\frac{\sqrt{}}{2}
$